\(2\dfrac{1}{6}+\dfrac{5}{6}:3-0,125\times\left(-2\right)^2\)

\(=\dfrac{13}{6}+\dfrac{5}{18}-0,125\times4\)

\(=\dfrac{22}{9}-0,5\)

\(=\dfrac{35}{18}\)

Ta có: \(\left(-\dfrac{5}{8}\right)-x:3\dfrac{5}{6}+7\dfrac{3}{4}=-2\)

\(\Leftrightarrow\dfrac{-5}{8}-x:\dfrac{23}{6}+\dfrac{31}{4}+2=0\)

\(\Leftrightarrow x:\dfrac{-23}{6}+\dfrac{73}{8}=0\)

\(\Leftrightarrow x\cdot\dfrac{-6}{23}=-\dfrac{73}{8}\)

\(\Leftrightarrow x=-\dfrac{73}{8}:\dfrac{-6}{23}=\dfrac{-73}{8}\cdot\dfrac{23}{-6}\)

hay \(x=\dfrac{1679}{48}\)

Vậy: \(x=\dfrac{1679}{48}\)

kết quả bằng 1679/48 nhé bạn 

\(1,A=-\dfrac{3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)

\(A=-\dfrac{3}{4}.\left(0,125-\dfrac{3}{2}\right):\dfrac{33}{16}-\dfrac{1}{4}\)

\(A=-\dfrac{3}{4}.\left(-\dfrac{11}{8}\right):\dfrac{33}{16}-\dfrac{1}{4}\)

\(A=\dfrac{33}{32}:\dfrac{33}{16}-\dfrac{1}{4}\)

\(A=\dfrac{33}{32}.\dfrac{16}{33}-\dfrac{1}{4}\)

\(A=\dfrac{1}{2}-\dfrac{1}{4}\)

\(A=\dfrac{2}{4}-\dfrac{1}{4}\)

\(A=\dfrac{1}{4}\)

\(D=6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)

\(D=\dfrac{77}{12}:\dfrac{13}{4}+\dfrac{45}{4}.\dfrac{2}{15}\)

\(D=\dfrac{77}{39}+\dfrac{3}{2}\)

\(D=\dfrac{271}{78}\)

\(C=\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)

\(C=\dfrac{5}{16}:0,125-\left(\dfrac{9}{4}-0,6\right).\dfrac{10}{11}\)

\(C=\dfrac{5}{16}:0,125-\dfrac{33}{20}.\dfrac{10}{11}\)

\(C=\dfrac{5}{2}-\dfrac{3}{2}\)

\(C=1\)

e) \(\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}.\dfrac{5}{7}+2\dfrac{3}{5}\)

= \(\dfrac{-3}{5}.\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\dfrac{13}{5}\)

= \(\dfrac{-3}{5}.1+\dfrac{13}{5}\)

= \(\dfrac{-3}{5}+\dfrac{13}{5}\)

= 2

\(A=\dfrac{-19}{9}.\dfrac{1}{2}-\dfrac{4}{11}.\dfrac{-11}{9}+\left(-\dfrac{2}{3}\right)=-\dfrac{23}{18}\)

\(B=\left(-\dfrac{15}{6}\right):\dfrac{-1}{2}+\dfrac{7}{-12}-\dfrac{1}{3}.\dfrac{-11}{2}=\dfrac{25}{4}\)

\(C=\dfrac{3}{4}.\left(-8\right)-\dfrac{1}{3}.\dfrac{-7}{2}-\dfrac{5}{18}=-\dfrac{46}{9}\)

\(A=\dfrac{-19}{18}+\dfrac{4}{9}-\dfrac{2}{3}=\dfrac{-19}{18}+\dfrac{8}{18}-\dfrac{12}{18}=\dfrac{-23}{18}\)

\(B=\dfrac{-5}{2}\cdot\dfrac{-2}{1}-\dfrac{7}{12}+\dfrac{11}{6}=\dfrac{5\cdot12-7+22}{12}=\dfrac{75}{12}=\dfrac{25}{4}\)

a) \(\dfrac{3}{22}\times\dfrac{3}{11}\times22\)

\(=\dfrac{3}{22}\times\dfrac{3}{11}\times\dfrac{22}{1}\)

\(=\dfrac{3\times3\times22}{22\times11\times1}\)

\(=\dfrac{9}{11}\)

b) \(\left(\dfrac{1}{3}+\dfrac{1}{6}\right)\times\dfrac{2}{5}\)

\(=\left(\dfrac{2}{6}+\dfrac{1}{6}\right)\times\dfrac{2}{5}\)

\(=\dfrac{3}{6}\times\dfrac{2}{5}\)

\(=\dfrac{1}{2}\times\dfrac{2}{5}\)

\(=\dfrac{2}{10}\)

\(=\dfrac{1}{5}\)

a: =3/22*22*3/11

=3*3/11

=9/11

b: =(2/6+1/6)*2/5

=1/2*2/5

=1/5

Câu 1:

a: \(\left(3x-15\right)=3^7:3^5\)

=>3x-15=9

=>3x=24

hay x=8

b: \(\left(4x+32\right)=43\cdot2^2\)

=>4x+32=172

=>4x=140

hay x=35

c: \(6^{2x-7}=216\)

=>2x-7=3

=>2x=10

hay x=5

d: \(5^x+5^{x+2}=650\)

\(\Leftrightarrow5^x\cdot26=650\)

\(\Leftrightarrow5^x=25\)

hay x=2

\(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\left(\dfrac{5}{3}\right)^6:\left(\dfrac{625}{343}\right)^2\)

\(=\left(\dfrac{3}{7}\cdot\dfrac{5}{3}\right)^6:\left(\dfrac{625}{343}\right)^2\)

\(=\dfrac{5^6}{7^6}:\dfrac{5^8}{7^6}=\dfrac{1}{25}\)